(x^2-4)(x^2+x-12)=0

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Solution for (x^2-4)(x^2+x-12)=0 equation:


Simplifying
(x2 + -4)(x2 + x + -12) = 0

Reorder the terms:
(-4 + x2)(x2 + x + -12) = 0

Reorder the terms:
(-4 + x2)(-12 + x + x2) = 0

Multiply (-4 + x2) * (-12 + x + x2)
(-4(-12 + x + x2) + x2(-12 + x + x2)) = 0
((-12 * -4 + x * -4 + x2 * -4) + x2(-12 + x + x2)) = 0
((48 + -4x + -4x2) + x2(-12 + x + x2)) = 0
(48 + -4x + -4x2 + (-12 * x2 + x * x2 + x2 * x2)) = 0
(48 + -4x + -4x2 + (-12x2 + x3 + x4)) = 0

Combine like terms: -4x2 + -12x2 = -16x2
(48 + -4x + -16x2 + x3 + x4) = 0

Solving
48 + -4x + -16x2 + x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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